如何在 Java 中使用 lambda 和方法引用實現 DoubleBinaryOperator?


DoubleBinaryOperator 是 java.util.function 包中定義的一個函式式 介面。它接受兩個型別為double 的引數作為輸入,併產生另一個double 值作為結果。DoubleBinaryOperator 介面可以用作lambda 表示式 方法 引用 的賦值目標,並且只有一個抽象方法 applyAsDouble()

語法

@FunctionalInterface
public interface DoubleBinaryOperator {
 double applyAsDouble(double left, double right);
}

示例-1

import java.util.function.DoubleBinaryOperator;

public class DoubleBinaryOperatorTest {
   public static void main(String args[]) {
      // using lambda expression
      DoubleBinaryOperator sum = (d1, d2) -> d1 + d2;
      DoubleBinaryOperator mul = (d1, d2) -> d1 * d2;
      DoubleBinaryOperator div = (d1, d2) -> d1 / d2;
      DoubleBinaryOperator sub = (d1, d2) -> d1 - d2;

      System.out.println("Sum = " + operate(sum, 15, 10));
      System.out.println("Multiplication = " + operate(mul, 15, 10));
      System.out.println("Division = " + operate(div, 15, 10));
      System.out.println("Subtraction = " + operate(sub, 15, 10));
   }
   private static double operate(DoubleBinaryOperator operator, double d1, double d2) {
      return operator.applyAsDouble(d1, d2);
   }
}

輸出

Sum = 25.0
Multiplication = 150.0
Division = 1.5
Subtraction = 5.0


示例-2

import java.util.function.DoubleBinaryOperator;

public class DoubleBinaryOperatorTest1 {
   public static void main(String[] args) {
       // Using Lambda Expression
      DoubleBinaryOperator lamdaTest = (d1, d2) -> DoubleBinaryOperatorTest1.mutiply(d1, d2);
      System.out.println(lamdaTest.applyAsDouble(7, 5));
      // Using Method reference
      DoubleBinaryOperator methodRefTest = DoubleBinaryOperatorTest1::mutiply;
      System.out.println(methodRefTest.applyAsDouble(10, 5));
   }
   public static double mutiply(double d1, double d2) {
      return d1 * d2;
   }
}

輸出

35.0
50.0

更新於:2020-07-13

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