如何從 MongoDB 集合中獲取唯一值?


若要獲取唯一值並忽略重複項,請在 MongoDB 中使用 distinct()。distinct() 會找到整個單一集合中特定欄位的唯一值,並以陣列形式返回結果。

讓我們建立一個包含文件的集合 −

> db.demo704.insertOne({"LanguageCode":"hi"});
{
   "acknowledged" : true,
   "insertedId" : ObjectId("5ea6ee18551299a9f98c93bd")
}
> db.demo704.insertOne({"LanguageCode":"en"});
{
   "acknowledged" : true,
   "insertedId" : ObjectId("5ea6ee1e551299a9f98c93be")
}
> db.demo704.insertOne({"LanguageCode":"hi"});
{
   "acknowledged" : true,
   "insertedId" : ObjectId("5ea6ee20551299a9f98c93bf")
}
> db.demo704.insertOne({"LanguageCode":"eo"});
{
   "acknowledged" : true,
   "insertedId" : ObjectId("5ea6ee2c551299a9f98c93c0")
}
> db.demo704.insertOne({"LanguageCode":"eu"});
{
   "acknowledged" : true,
   "insertedId" : ObjectId("5ea6ee2f551299a9f98c93c1")
}
> db.demo704.insertOne({"LanguageCode":"fo"});
{
   "acknowledged" : true,
   "insertedId" : ObjectId("5ea6ee35551299a9f98c93c2")
}
> db.demo704.insertOne({"LanguageCode":"fo"});
{
   "acknowledged" : true,
   "insertedId" : ObjectId("5ea6ee37551299a9f98c93c3")
}

藉助 find() 方法顯示某個集合中的所有文件 −

> db.demo704.find();

這會生成以下輸出 −

{ "_id" : ObjectId("5ea6ee18551299a9f98c93bd"), "LanguageCode" : "hi" }
{ "_id" : ObjectId("5ea6ee1e551299a9f98c93be"), "LanguageCode" : "en" }
{ "_id" : ObjectId("5ea6ee20551299a9f98c93bf"), "LanguageCode" : "hi" }
{ "_id" : ObjectId("5ea6ee2c551299a9f98c93c0"), "LanguageCode" : "eo" }
{ "_id" : ObjectId("5ea6ee2f551299a9f98c93c1"), "LanguageCode" : "eu" }
{ "_id" : ObjectId("5ea6ee35551299a9f98c93c2"), "LanguageCode" : "fo" }
{ "_id" : ObjectId("5ea6ee37551299a9f98c93c3"), "LanguageCode" : "fo" }

以下查詢可以獲取唯一值,並在陣列中顯示結果 −

> db.demo704.distinct("LanguageCode");

這會生成以下輸出 −

[ "hi", "en", "eo", "eu", "fo" ]

更新於: 14-5-2020

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