如何使用 MySQL TRIM() 刪除所有行中的空白字元並更新表?
假設某張表中有許多值在表的列中帶有空白字元,則這會浪費空間。我們可以使用 TRIM() 函式來移除所有行中的空白字元,並在一個查詢中更新該表。以“Employee”為例,在其所有行中含有空白字元,將展示此概念 −
示例
mysql> Select * from Employee; +------+----------------------+----------------------+----------------------+ | Id | Name | Address | Department | +------+----------------------+----------------------+----------------------+ | 100 | Raman | Delhi | IT | | 101 | Mohan | Haryana | History | | 102 | Shyam | Chandigarh | ENGLISH | | 103 | Sukhjeet Singh | Patiala | Computer Engg. | | 104 | Bimal Roy | Calcutta | Computer Engg. | +------+----------------------+----------------------+----------------------+ 5 rows in set (0.00 sec)
我們可以從以上結果集中看到,Employee 表在所有行中都帶有許多空白字元。可以透過以下查詢移除並更新這些空白字元 −
mysql> Update Employee SET Id = TRIM(Id), Name = TRIM(Name), Address = TRIM(Address), DEPARTMENT = TRIM(Department); Query OK, 5 rows affected (0.24 sec) Rows matched: 5 Changed: 5 Warnings: 0 mysql> Select * from Employee; +------+----------------+------------+----------------+ | Id | Name | Address | Department | +------+----------------+------------+----------------+ | 100 | Raman | Delhi | IT | | 101 | Mohan | Haryana | History | | 102 | Shyam | Chandigarh | ENGLISH | | 103 | Sukhjeet Singh | Patiala | Computer Engg. | | 104 | Bimal Roy | Calcutta | Computer Engg. | +------+----------------+------------+----------------+ 5 rows in set (0.00 sec)
我們可以從以上結果集中看到,所有空白字元都已移除,並且該表已更新。
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