如何在 MongoDB 中根據陣列中匹配物件的數目查詢文件?
我們來看一個例子,建立一個帶有文件的集合 -
> db.demo694.insertOne(
... {
... "details" :
... [
... {
... "Name" : "Chris",
... Age:21
... },
... {
... "Name" : "David",
... Age:22
... }
... ]
... }
... );
{
"acknowledged" : true,
"insertedId" : ObjectId("5ea59279ece4e5779399c07f")
}
> db.demo694.insertOne(
... {
... "details" :
... [
... {
... "Name" : "Bob",
... Age:21
... },
... {
... "Name" : "Mike",
... Age:23
... }
... ]
... }
... );
{
"acknowledged" : true,
"insertedId" : ObjectId("5ea5927aece4e5779399c080")
}
> db.demo694.insertOne(
... {
... "details" :
... [
... {
... "Name" : "Chris",
... Age:21
... },
... {
... "Name" : "Carol",
... Age:22
... }
... ]
... }
... );
{
"acknowledged" : true,
"insertedId" : ObjectId("5ea5927aece4e5779399c081")
}使用 find() 方法從集合中顯示所有文件 -
> db.demo694.find();
這會產生以下輸出 -
{ "_id" : ObjectId("5ea59279ece4e5779399c07f"), "details" : [ { "Name" : "Chris", "Age" : 21 }, { "Name" : "David", "Age" : 22 } ] }
{ "_id" : ObjectId("5ea5927aece4e5779399c080"), "details" : [ { "Name" : "Bob", "Age" : 21 }, { "Name" : "Mike", "Age" : 23 } ] }
{ "_id" : ObjectId("5ea5927aece4e5779399c081"), "details" : [ { "Name" : "Chris", "Age" : 21 }, { "Name" : "Carol", "Age" : 22 } ] }以下是根據陣列中匹配物件的數目在 MongoDB 中查詢文件的查詢 -
> nameChrisAge21= function () {
... var inc = 0;
... this.details.forEach(function (d) {
... if (d.Name == "Chris" && d.Age == 21) {
... inc= inc + 1;
... }
... });
... if (inc >= 1) {
... return true;
... }
... }
function () {
var inc = 0;
this.details.forEach(function (d) {
if (d.Name == "Chris" && d.Age == 21) {
inc= inc + 1;
}
});
if (inc >= 1) {
return true;
}
}
> db.demo694.find({$where:nameChrisAge21});這會產生以下輸出 -
{ "_id" : ObjectId("5ea59279ece4e5779399c07f"), "details" : [ { "Name" : "Chris", "Age" : 21 }, { "Name" : "David", "Age" : 22 } ] }
{ "_id" : ObjectId("5ea5927aece4e5779399c081"), "details" : [ { "Name" : "Chris", "Age" : 21 }, { "Name" : "Carol", "Age" : 22 } ] }
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