從MongoDB中獲取隨機記錄嗎?


要從MongoDB中獲得隨機記錄,可以使用聚合函式。語法如下

db.yourCollectionName.aggregate([{$sample:{size:1}}]);

為了理解以上語法,讓我們建立一個帶有一些文件的集合。建立集合的查詢如下

>db.employeeInformation.insert({"EmployeeId":1,"EmployeeName":"Maxwell","EmployeeAge":26});
WriteResult({ "nInserted" : 1 })
>db.employeeInformation.insert({"EmployeeId":2,"EmployeeName":"David","EmployeeAge":25});
WriteResult({ "nInserted" : 1 })
>db.employeeInformation.insert({"EmployeeId":3,"EmployeeName":"Carol","EmployeeAge":24});
WriteResult({ "nInserted" : 1 })
>db.employeeInformation.insert({"EmployeeId":4,"EmployeeName":"Bob","EmployeeAge":28});
WriteResult({ "nInserted" : 1 })
>db.employeeInformation.insert({"EmployeeId":5,"EmployeeName":"Sam","EmployeeAge":27);
WriteResult({ "nInserted" : 1 })

現在,您可以藉助find()方法顯示集合中的所有文件。該查詢如下

> db.employeeInformation.find().pretty();

輸出如下

{
   "_id" : ObjectId("5c6d3079734e98fc0a434ae5"),
   "EmployeeId" : 1,
   "EmployeeName" : "Maxwell",
   "EmployeeAge" : 26
}
{
   "_id" : ObjectId("5c6d308c734e98fc0a434ae6"),
   "EmployeeId" : 2,
   "EmployeeName" : "David",
   "EmployeeAge" : 25
}
{
   "_id" : ObjectId("5c6d309d734e98fc0a434ae7"),
   "EmployeeId" : 3,
   "EmployeeName" : "Carol",
   "EmployeeAge" : 24
}
{
   "_id" : ObjectId("5c6d30ab734e98fc0a434ae8"),
   "EmployeeId" : 4,
   "EmployeeName" : "Bob",
   "EmployeeAge" : 28
}
{
   "_id" : ObjectId("5c6d30bb734e98fc0a434ae9"),
   "EmployeeId" : 5,
   "EmployeeName" : "Sam",
   "EmployeeAge" : 27
}

以下是獲取隨機記錄的查詢

> db.employeeInformation.aggregate([{$sample:{size:1}}]).pretty();

輸出如下

{
   "_id" : ObjectId("5c6d30bb734e98fc0a434ae9"),
   "EmployeeId" : 5,
   "EmployeeName" : "Sam",
   "EmployeeAge" : 27
}

讓我們使用相同的查詢獲取另一條隨機記錄

> db.employeeInformation.aggregate([{$sample:{size:1}}]).pretty();

輸出如下

{
   "_id" : ObjectId("5c6d308c734e98fc0a434ae6"),
   "EmployeeId" : 2,
   "EmployeeName" : "David",
   "EmployeeAge" : 25
}

更新於: 2019 年 7 月 30 日

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