Python 中帶有不常用字元的連線字串？

這裡給出了兩個字串，首先我們必須從第一個字串中刪除所有常見元素，並且第二個字串的不常用字元必須與第一個字串的不常用元素連線。

示例

Input >> first string::AABCD
Second string:: MNAABP
Output >> CDMNP

演算法

Uncommonstring(s1,s2)
/* s1 and s2 are two string */
Step 1: Convert both string into set st1 and st2.
Step 2: use the intersection of two sets and get common characters.
Step 3: now separate out characters in each string which are not common in both string.
Step 4: join each character without space to get a final string.

示例程式碼

# Concatination of two uncommon strings 
def uncommonstring(s1, s2):
# convert both strings into set
   st1 = set(s1)
   st2 = set(s2)
   # take intersection of two sets to get list of common characters 
   lst = list(st1 & st2)
   finallist = [i for i in s1 if i not in lst] + \ [i for i in s2 if i not in lst]
   print("CONCATENATED STRING IS :::", ''.join(finallist))
# Driver program
if __name__ == "__main__":
   s1 =input("Enter the String ::")
   s2=input("Enter the String ::")
   uncommonstring(s1,s2)

輸出

Enter the String ::abcde
Enter the String ::bdkl
CONCATEATED STRINGIS ::: acekl

karthikeya Boyini

更新於： 30-Jul-2019

807 次瀏覽

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